Find answers to questions asked by student like you, Calculate the de Broglie wavelength of a proton moving at 2.42 ✕ 108 m/s. by x(t)=Asin(wt), where A is the a... A: For a simple harmonic oscillator the force acting is given by , The angular speed is given by, (a) Zero (b) Infinity (c) Equal to the kinetic energy of the proton (d) Greater than the kinetic energy of the proton. Our kinetic energy is in units of electron volts, but we’d like to convert this to units of joules to be consistent with the rest of our values. We want to solve for the de Broglie wavelength of this proton; we’ll call that . Hence, KE = (½) pv, the kinetic energy of the electron is greater than the kinetic energy of the proton. Then the kinetic energy of the electron is? a = (2.00i + 5.00j) m/s². The nucleus is initially at rest. Question. The waves which travel in the form of oscillating electric and magnetic waves are called electromagnetic waves. *Response times vary by subject and question complexity. Looking up the mass of a proton in a table, we find that it’s approximately equal to 1.67 times 10 to the negative 27th kilograms. The angular speed will be time derivative of angular position. Read the question carefully, and you should see it says proton... That is, a mass-ive particle with rest mass m_p = 1.673 xx 10^(-27) "kg". A→=-18.0 mi^ By the conservation of momentum principle, we can assume that the momenta of the α-particle of mass m and the residual nucleus will be equal and opposite. One electron volt is equal to 1.602 times 10 to the negative 19th joules. Problem #2: What is the wavelength in meters of a proton traveling at 255,000,000 m/s (which is 85% of the speed of light)? de Broglie wavelength λ of a particle = h /P a) since mass of proton is more than electron and speed is same , momentum of proton is more . Nagwa is an educational technology startup aiming to help teachers teach and students learn. Question 11: The operation of the electron microscope depends on the: The wave nature of the electron particles is utilized in the electron microscope. The photon’s energy depends only on the frequency of the photon. However, we weren’t given the proton’s speed but we were given its kinetic energy. *Response times vary by subject and question complexity. de-Broglie wavelength = (6.625×10-14)/√(2×9.11×10-31×1.6×10-17×400). Median response time is 34 minutes and may be longer for new subjects. In the annihilation of electron with positron the masses of electron and positron are converted in electromagnetic energy. (b) less than the kinetic energy of the particle. The de Broglie wavelength is inversely proportional to momentum. (This is why the limiting resolution of an electron microscope is much higher than that of an optical microscope.) Copyright © 2020 NagwaAll Rights Reserved. De Broglie wavelength of proton will be less . F=-kx Since energy is same and mass of proton is more , it's momentum will be more . The electron and the proton have the same de Broglie wavelength, which means their momenta are the same. Since the mass of the proton is greater than the mass of the electron, its speed is less than the speed of the electron. Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*. A: conversion between C and kelvin scale is  c) Using P = √(2Km) . 10: A nucleus of mass M at rest emits an α-particle of mass m. The de Broglie wavelengths of the α-particle and residual nucleus will be in the ratio. Click hereto get an answer to your question ️ If a proton and an electron have the same de Broglie wavelength, the ratio of the velocity of proton to the velocity of electron will be nearly m/sec. proton Compton wavelength †: Numerical value: 1.321 409 855 39 x 10-15 m : Standard uncertainty: 0.000 000 000 40 x 10-15 m : Relative standard uncertainty: 3.1 x 10-10: Concise form 9: An electron and a proton have the same de Broglie wavelength. (c) Equal to the kinetic energy of the proton, (d) Greater than the kinetic energy of the proton. Electron microscope makes use of the matter waves associated with fast-moving electrons. (Assume the mass of the proton to be 1.673 x 10¯ 27 kg.) Let’s call this kinetic energy of 2.0 megaelectron volts capital KE. Now that we have values for ℎ, , and KE, we’re ready to plug into this equation. What is the de Broglie wavelength of a proton whose kinetic energy is 2.0 megaelectron volts? Nagwa uses cookies to ensure you get the best experience on our website. When we recall that momentum is equal to an object’s mass times its velocity, , that means we can apply the de Broglie wavelength equation to our scenario by writing that the wavelength of the proton equals Planck’s constant divided by the proton’s mass times its speed. And in general, the kinetic energy of an object, KE, is equal to one half the mass of the object times its speed squared. Wavelength of photon is depends on the source from which it emitted.. Photon of the X-ray spectra has the different wavelength than the photon of the gamma ray spectra..

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